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(defvar *prog-input*)
;;; After running file, if you enter a blank line, code will work on each
;;; line of input, until "end" is typed.
;;; Otherwise, the input is taken as a filename and code will be executed
;;; over each line in the file until EOF.
(let ((ui (read-line)))
(if (equal ui "")
(setq *prog-input* *standard-input*)
(setq *prog-input* (open ui))))
(let
((inpt (read-line *prog-input* NIL)) (i 1) (stacks '(())) (si 0))
(loop until (char= (char inpt 1) #\1) do
(loop until (>= i (length inpt)) do
(if (<= (length stacks) si)
(setq stacks (append stacks (list NIL NIL) ))) ; ZERO idea why I can't just append '(())
(if (not (char= (char inpt i) #\Space))
(setf (nth si stacks) (append (nth si stacks) (list (char inpt i)))))
(setq si (+ si 1) i (+ i 4)))
(setq i 1 si 0)
(setq inpt (read-line *prog-input* NIL)))
(read-line *prog-input* NIL)
(setq inpt (read-line *prog-input* NIL))
(loop until (or (string= inpt "end") (not inpt)) do
(setq si (- (parse-integer inpt :junk-allowed T :start (position #\Space inpt :start (position #\f inpt))) 1))
(setq i (- (parse-integer inpt :junk-allowed T :start (position #\Space inpt :start (position #\t inpt))) 1))
(dotimes (x (parse-integer inpt :junk-allowed T :start (position #\Space inpt)))
(push (pop (nth si stacks)) (nth i stacks)))
(setq inpt (read-line *prog-input* NIL)))
(loop for x in stacks do
(prin1 (car x))))
(if (not (eq *prog-input* *standard-input*))
(close *prog-input*))
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