diff options
Fixed triangle area and fixed typo in trianglePrimeter function name
1 files changed, 5 insertions, 3 deletions
| -rw-r--r-- | Year 1/Programming introduction/Practice-02.10.21.cpp | 8 |
diff --git a/Year 1/Programming introduction/Practice-02.10.21.cpp b/Year 1/Programming introduction/Practice-02.10.21.cpp index f000ab8..0c524f3 100644 --- a/Year 1/Programming introduction/Practice-02.10.21.cpp +++ b/Year 1/Programming introduction/Practice-02.10.21.cpp @@ -79,7 +79,7 @@ void ex4() { // Напишете функция която намира обиколката на триъгълник определен по // подадени три точки -double trianglePerimiter(int x1, int y1, int x2, int y2, int x3, int y3) { +double trianglePerimeter(int x1, int y1, int x2, int y2, int x3, int y3) { return pointDistance(x1, y1, x2, y2) + pointDistance(x1, y1, x3, y3) + pointDistance(x2, y2, x3, y3); } @@ -87,7 +87,7 @@ void ex5() { int x1, y1, x2, y2, x3, y3; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; - cout << trianglePerimiter(x1, y1, x2, y2, x3, y3) << endl; + cout << trianglePerimeter(x1, y1, x2, y2, x3, y3) << endl; } // Задача шеста: @@ -115,7 +115,9 @@ void ex6() { // три точки. double triangleArea(int x1, int y1, int x2, int y2, int x3, int y3) { - return pointDistance(x1, y1, x2, y2) * pointDistance(x1, y1, x3, y3) * pointDistance(x2, y2, x3, y3); + double a = pointDistance(x1, y1, x2, y2), b = pointDistance(x1, y1, x3, y3), c = pointDistance(x2, y2, x3, y3); + double p = (a + b + c) / 2; + return sqrt(p * (p - a) * (p - b) * (p - c)); // Heron's formula } void bonus() { |
