[DAA/H1] Fixed typo with z in ex 2

2 files changed, 1 insertions, 1 deletions

diff --git a/Year 2/Design and analysis of algorithms/Homeworks/Homework1.pdf b/Year 2/Design and analysis of algorithms/Homeworks/Homework1.pdf
index de29aab..b96b97e 100644
--- a/Year 2/Design and analysis of algorithms/Homeworks/Homework1.pdf
+++ b/Year 2/Design and analysis of algorithms/Homeworks/Homework1.pdf
diff --git a/Year 2/Design and analysis of algorithms/Homeworks/Homework1.tex b/Year 2/Design and analysis of algorithms/Homeworks/Homework1.tex
index b631e3d..762021e 100644
--- a/Year 2/Design and analysis of algorithms/Homeworks/Homework1.tex
+++ b/Year 2/Design and analysis of algorithms/Homeworks/Homework1.tex
@@ -95,7 +95,7 @@
 	x & = 6(i+1) \\ 
 	y & = 1+\sum_{j=0}^i6j = 1+3i(i+1) \\
 	z & = \sum_{j=0}^{i-1}(1 + 3j(j+1)) = i + 3 \sum_{j=0}^{i-1}j(j+1) = i + 3 \left( \sum_{j=0}^{i-1} j^2 + \sum_{j=0}^{i-1} j \right) \\
-	& = i + 3 \left( \frac{(i-1)i(2(i-1)+1)}{6} + \frac{(i-1)i}{2} \right) = i + 3 \left( \frac{2i^3-2i^2}{6} \right) = i^3
+	& = i + 3 \left( \frac{(i-1)i(2(i-1)+1)}{6} + \frac{(i-1)i}{2} \right) = i + 3 \left( \frac{2i^3-2i}{6} \right) = i^3
 \end{align*}
 
 \textit{База:} При първото достигане на ред 4, $i = 0$ и променливите $x, y, z$ имат стойностите, зададени на ред 2. В същото време, при инварианта $x = 6(0+1) = 6, y = 1+3.0.(0+1) = 1, z = \sum\limits_{j=0}^{-1}(1 + 3j(j+1)) = 0$.