Website Summary Files Commits Branches @commit @diff @stats
path: root / pract_KN / pract. 03 / solutions / 7.cpp
diff options
context:
space:
mode:
Commitd49b98e349a5c51bee50d5b707825e2a06730684 (patch)
Author
 Stoycho Kyosev <68247567+stoychoX@users.noreply.github.com>
2021-10-25 15:28:54 +0300
Committer
 GitHub <noreply@github.com>
2021-10-25 15:28:54 +0300
Files7b6ddac365d0f506b509c56e9c55c5eed6cd3478 /pract_KN/pract. 03/solutions/7.cpp
Introduction_to_programming_FMI-d49b98e349a5c51bee50d5b707825e2a06730684.tar
Introduction_to_programming_FMI-d49b98e349a5c51bee50d5b707825e2a06730684.tar.gz
Introduction_to_programming_FMI-d49b98e349a5c51bee50d5b707825e2a06730684.zip
Parent5b9017aa843d1bc2b8e83cb89c80ab2667d32470 (diff)
Add files via upload
1 files changed, 54 insertions, 0 deletions
-rw-r--r--pract_KN/pract. 03/solutions/7.cpp54
diff --git a/pract_KN/pract. 03/solutions/7.cpp b/pract_KN/pract. 03/solutions/7.cpp
new file mode 100644
index 0000000..4ddc889
--- /dev/null
+++ b/pract_KN/pract. 03/solutions/7.cpp
@@ -0,0 +1,54 @@
+#include<iostream>
+#include<thread>
+#include<chrono>
+
+int main() {
+ int number = 0;
+ std::cin >> number;
+
+ if (number % 2 == 0) {
+ ++number;
+ }
+
+ for (int i = 0; i <= number; i += 2) {
+ for (int j = 0; j < i; j += 2) {
+ std::cout << " ";
+ }
+
+ for (int j = 0; j < number - i; j++) {
+ std::cout << "*";
+ }
+ //for (int j = 0; j < i; j++) {
+ //std::cout << " ";
+ //}
+ //std::cout << "--Now I print " << i / 2 << " blank spaces and " << number - i << " * symbols. Now i keep printing...";
+ std::cout << std::endl;
+ }
+
+ for (int i = number - 1; i >= 0; i -= 2) {
+ for (int j = 0; j < i; j += 2) {
+ std::cout << " ";
+ }
+
+ for (int j = 0; j < number - i; j++) {
+ std::cout << "*";
+ }
+ //for (int j = 0; j < i; j++) {
+ //std::cout << " ";
+ //}
+ //std::cout << "--Now I print " << i / 2 << " blank spaces and " << number - i << " * symbols. Now i keep printing...";
+ std::cout << std::endl;
+ }
+}
+ /*
+ Задачата може да се сведе до две по - прости задачи. До принтиране на триъгълник и същия триъгълнк наобратно.
+ Задачата за триъгълникът пък може да се сведе до просто принтиране на правилната последователност от
+ разстояния и звездички.
+ ако входа е 15 имаме (разстояния-звездички)
+ 0-15
+ 1-13
+ 2-11
+ ...
+
+ може да махнете коментарите което ще извежда колко празни пространства и звездички програмата извежда всяка стъпка
+ */