From 6e34b60dddad5971436f24edd927f23a206e91cc Mon Sep 17 00:00:00 2001
From: Syndamia <kamen.d.mladenov@protonmail.com>
Date: Fri, 29 Oct 2021 16:12:56 +0300
Subject: Added old self learning latex files

---
 LaTeX/test.tex | 49 +++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 49 insertions(+)
 create mode 100644 LaTeX/test.tex

(limited to 'LaTeX/test.tex')

diff --git a/LaTeX/test.tex b/LaTeX/test.tex
new file mode 100644
index 0000000..8425092
--- /dev/null
+++ b/LaTeX/test.tex
@@ -0,0 +1,49 @@
+\documentclass{article}
+
+\usepackage{amsmath}
+
+\usepackage{polyglossia}
+\setmainlanguage{russian} % alternative for lack of bulgarian support
+\setotherlanguage{english}
+\newfontfamily\russianfont{Times New Roman}
+
+\begin{document}
+\huge
+
+\begin{center}
+Теореми за разположение на корени на уравнение от типа $ax^2+bx+c, a \neq 0$
+\end{center}
+
+\begin{center}
+
+\textbf{Теорема 1:} когато искаме\linebreak
+$x_1 < p < x_2$\linebreak
+(тоест $x_1 < p$ и $x_2 \geq p$),\linebreak
+трябва\linebreak
+$a * f(p) < 0$
+
+\end{center}
+
+\begin{center}
+
+\textbf{Теорема 2:} когато искаме\linebreak
+$x_1 < p$ и $x_2 < p$\linebreak
+трябва\linebreak
+$a * f(p) > 0$,\linebreak
+$D \geq 0$,\linebreak
+$-\frac{b}{2a} < p$
+
+\end{center}
+
+\begin{center}
+
+\textbf{Теорема 3:} когато искаме\linebreak
+$x_1 > p$ и $x_2 > p$\linebreak
+трябва\linebreak
+$a * f(p) > 0$,\linebreak
+$D \geq 0$,\linebreak
+$-\frac{b}{2a} > p$
+
+\end{center}
+
+\end{document}
\ No newline at end of file
-- 
cgit v1.2.3